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NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.2

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NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.2

by Unbeaten Ingenious
(30.6k points)
in Maths 9th
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NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.2

3 Answers

by Unbeaten Ingenious
(30.6k points)
0 votes

1. Visualise 3.765 on the number line, using successive magnification.
 3.765 lies between 3 and 4.
Let us divide the interval (3, 4) into 10 equal parts. 

Since, 3.765 lies between 3.7 and 3.8. We again magnify the interval [3.7, 3.8] by dividing it further into 10 parts and concentrate the distance between 3.76 and 3.77.
The number 3.765 lies between 3.76 and 3.77. Therefore we further magnify the interval [3.76, 3.77] into 10 equal parts.
Now, the point corresponding to 3.765 is clearly located, as shown in Fig. (iii) above.

by Unbeaten Ingenious
(30.6k points)
0 votes

1. Visualise 3.765 on the number line, using successive magnification.
 3.765 lies between 3 and 4.
Let us divide the interval (3, 4) into 10 equal parts. 

Since, 3.765 lies between 3.7 and 3.8. We again magnify the interval [3.7, 3.8] by dividing it further into 10 parts and concentrate the distance between 3.76 and 3.77.
The number 3.765 lies between 3.76 and 3.77. Therefore we further magnify the interval [3.76, 3.77] into 10 equal parts.
Now, the point corresponding to 3.765 is clearly located, as shown in Fig. (iii) above.

by Unbeaten Ingenious
(30.6k points)
0 votes

1. Visualise 3.765 on the number line, using successive magnification.
 3.765 lies between 3 and 4.
Let us divide the interval (3, 4) into 10 equal parts. 

Since, 3.765 lies between 3.7 and 3.8. We again magnify the interval [3.7, 3.8] by dividing it further into 10 parts and concentrate the distance between 3.76 and 3.77.
The number 3.765 lies between 3.76 and 3.77. Therefore we further magnify the interval [3.76, 3.77] into 10 equal parts.
Now, the point corresponding to 3.765 is clearly located, as shown in Fig. (iii) above.

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