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# NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.2

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# NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.2

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NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.2

by Unbeaten Ingenious
(30.6k points)

1. Visualise 3.765 on the number line, using successive magnification.
3.765 lies between 3 and 4.
Let us divide the interval (3, 4) into 10 equal parts.

Since, 3.765 lies between 3.7 and 3.8. We again magnify the interval [3.7, 3.8] by dividing it further into 10 parts and concentrate the distance between 3.76 and 3.77.
The number 3.765 lies between 3.76 and 3.77. Therefore we further magnify the interval [3.76, 3.77] into 10 equal parts.
Now, the point corresponding to 3.765 is clearly located, as shown in Fig. (iii) above.

by Unbeaten Ingenious
(30.6k points)

1. Visualise 3.765 on the number line, using successive magnification.
3.765 lies between 3 and 4.
Let us divide the interval (3, 4) into 10 equal parts.

Since, 3.765 lies between 3.7 and 3.8. We again magnify the interval [3.7, 3.8] by dividing it further into 10 parts and concentrate the distance between 3.76 and 3.77.
The number 3.765 lies between 3.76 and 3.77. Therefore we further magnify the interval [3.76, 3.77] into 10 equal parts.
Now, the point corresponding to 3.765 is clearly located, as shown in Fig. (iii) above.

by Unbeaten Ingenious
(30.6k points)

1. Visualise 3.765 on the number line, using successive magnification.
3.765 lies between 3 and 4.
Let us divide the interval (3, 4) into 10 equal parts.

Since, 3.765 lies between 3.7 and 3.8. We again magnify the interval [3.7, 3.8] by dividing it further into 10 parts and concentrate the distance between 3.76 and 3.77.
The number 3.765 lies between 3.76 and 3.77. Therefore we further magnify the interval [3.76, 3.77] into 10 equal parts.
Now, the point corresponding to 3.765 is clearly located, as shown in Fig. (iii) above.

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